CBSE Class 12 · 2010 · Modern PhysicsShort Answer

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An electron is accelerated through a potential difference of 64 volts. What is the de-Broglie wavelength associated with it? To which part of the electromagnetic spectrum does this value of wavelength correspond?

Answer: $λ \approx 1.53 \overset{˚}{A}$ ; X-ray region.

Solution

For an electron accelerated through

V

volts,

λ = \frac{12.27}{V} \overset{˚}{A} = \frac{12.27}{64} = \frac{12.27}{8} \approx 1.53 \overset{˚}{A} .

A wavelength of about

1.5 \overset{˚}{A}

lies in the X-ray region of the electromagnetic spectrum.

λ \approx 1.53 \overset{˚}{A} (X-ray region)

CBSE Class 12 Board · 2010 · Subjective

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