The variation of the stopping potential V0 with the frequency ν of the light incident on two different photosensitive surfaces M1 and M2 is shown in the figure. Identify the surface which has the greater value of work function.
Answer: Surface M2 (larger threshold frequency).
Solution
The intercept of each line on the frequency axis is the threshold frequency ν0, and the work function is ϕ0=hν0. The line for M2 meets the frequency axis at the larger ν0, so M2 has the greater work function.