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CBSE Class 12 · 2020 · Modern PhysicsVery Short Answer

The nuclear radius of

_{13}^{27} Al

is 3.6 fermi. Find the nuclear radius of

_{29}^{64} Cu

.

Answer: $4.8 fermi$

Solution

R = R_{0} A^{1/3}

, so

\frac{R _{Cu}}{R _{Al}} = (\frac{64}{27})^{1/3} = \frac{4}{3} \Rightarrow R_{Cu} = \frac{4}{3} \times 3.6 = 4.8 fermi .

R_{Cu} = 4.8 fermi

CBSE Class 12 Board · 2020 · Subjective

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