CBSE Class 12 · 2008 · All India · Modern PhysicsVery Short Answer

The potential energy between two nucleons inside a nucleus is minimum at a distance of about

The variation of the stopping potential $V_0$ with the frequency $\nu$ of the incident radiation for four metals A, B, C and D is shown in the figure. For the same frequency of incident radiation producing photo-electrons in all metals, the kinetic energy of photo-electrons will …

The energy of an electron in the ground state of a hydrogen atom is $-13.6$ eV. The kinetic and potential energy of the electron in the first excited state will be

Assertion (A): An alpha particle is moving towards a gold nucleus. The impact parameter is maximum for the scattering angle of $180^{\circ }$.
Reason (R): The impact parameter in an alpha particle scattering experiment does not depend upon the atomic number of the target nucleus.

Calculate the energy released / absorbed (in MeV) in the nuclear reaction ${}_1^1\mathrm{H}+{}_1^3\mathrm{H}\to {}_1^2\mathrm{H}+{}_1^2\mathrm{H}$. Given $m{(}_1^1\mathrm{H})=1.007825u$, $m{(}_1^2\mathrm{H})=2.014102u$, …

A proton of energy 1.6 MeV approaches a gold nucleus $(Z=79)$. Find the distance of its closest approach.