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CBSE Class 12 · 2010 · SemiconductorsShort Answer

Identify the gate equivalent to the 'dotted box' shown in the figure and give its symbol and truth table.

Solution

Each input is inverted and the inverted signals feed a NOR gate, so

Y = \overline{\overline{A} + \overline{B}} = \overline{\overline{A}} \cdot \overline{\overline{B}} = A \cdot B .

Hence the box is an AND gate (D-shaped symbol).
Truth table:

00 \to 0, 10 \to 0, 01 \to 0, 11 \to 1

.

Y = A \cdot B (AND)

CBSE Class 12 Board · 2010 · Subjective

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