CBSE Class 12 · 2017 · Delhi · Magnetic Properties of MatterVery Short Answer

At a place, the horizontal component of the earth's magnetic field is

B

and the angle of dip is

6 0^{\circ}

. What is the value of the horizontal component of the earth's magnetic field at the (magnetic) equator?

Answer: $2 B$ .

Solution

At the given place

B_{H} = B_{E} cos δ

, so

B = B_{E} cos 6 0^{\circ} = \frac{1}{2} B_{E} \Rightarrow B_{E} = 2 B .

Earth's total field

B_{E}

is the same place-constant here; at the magnetic equator

δ = 0^{\circ}

, so the horizontal component is

B_{H}^{'} = B_{E} cos 0^{\circ} = B_{E} = 2 B .

B_{H}^{'} = 2 B

CBSE Class 12 Board · 2017 · Delhi · Subjective