Draw equipotential surfaces corresponding to a field that uniformly increases in magnitude but remains constant along Z-direction. How are these surfaces different from that of a constant electric field along Z-direction?
Solution
Since E=−dzdV, the spacing dz between equipotentials for a fixed potential step is inversely proportional to the field. For a field increasing along Z, the perpendicular planes are drawn closer and closer together as Z increases. For a constant field along Z the planes are equally spaced.