CBSE Class 12 · 2017 · ElectrostaticsVery Short Answer

Draw a plot showing variation of electric field with distance from the centre of a solid conducting sphere of radius

R

, having a charge

+ Q

on its surface.

Solution

The charge resides on the surface of the conductor. Inside (

r < R

) the enclosed charge is zero so

E = 0

. At the surface the field jumps to

\frac{1}{4 π ε _{0}} \frac{Q}{R ^{2}}

, and outside (

r > R

) it behaves like that of a point charge, decreasing as

1/ r^{2}

CBSE Class 12 Board · 2017 · Subjective

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